(x+1)(x+1)=x^2

Solution for (x+1)(x+1)=x^2 equation:

Simplifying
(x + 1)(x + 1) = x2

Reorder the terms:
(1 + x)(x + 1) = x2

Reorder the terms:
(1 + x)(1 + x) = x2

Multiply (1 + x) * (1 + x)
(1(1 + x) + x(1 + x)) = x2
((1 * 1 + x * 1) + x(1 + x)) = x2
((1 + 1x) + x(1 + x)) = x2
(1 + 1x + (1 * x + x * x)) = x2
(1 + 1x + (1x + x2)) = x2

Combine like terms: 1x + 1x = 2x
(1 + 2x + x2) = x2

Add '-1x2' to each side of the equation.
1 + 2x + x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
1 + 2x + 0 = x2 + -1x2
1 + 2x = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
1 + 2x = 0

Solving
1 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = 0 + -1
2x = 0 + -1

Combine like terms: 0 + -1 = -1
2x = -1

Divide each side by '2'.
x = -0.5

Simplifying
x = -0.5